kiki1171 kiki1171
  • 09-02-2017
  • Mathematics
contestada

Don't know how to do this

Dont know how to do this class=

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jdoe0001 jdoe0001
  • 09-02-2017
[tex]\bf c^2=a^2+b^2\qquad \begin{cases} c=x\\ a=2\sqrt{2}\\ b=\sqrt{13} \end{cases}\implies x^2=(2\sqrt{2})^2+(\sqrt{13})^2 \\ \quad \\\\ x^2=2^2\sqrt{2^2}+\sqrt{13^2}\impliedby \textit{with the exponent distributed} \\\\ x^2=4\cdot 2+13\implies x^2=8+13\implies x^2=21 \\\\ \sqrt{x^2}=\sqrt{21}\impliedby \textit{now, we took }\sqrt{\qquad }\textit{ to both sides} \\\\ x=\pm \sqrt{21}[/tex]
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