Answer:
(2/x²y³)
Step-by-step explanation:
(2(x^-2)y)/(y^4)
x^-2 can also be written as (1/x²)
(2(1/x²)y)/(y^4)
(2/x²)(y)/(y^4)
(2y/x²)/(y^4)
this can also be written as (2y/x²) × (1/y^4)
= 2y/(x² × y^4)
WHEN THE SAME VARIABLE IS DIVIDED THEIR POWERS ARE SUBTRACTED
= (2/x²y³) (we got y³ by y^1 /y^4 The powers got subtracted)
