vnagalakshmi1991 vnagalakshmi1991
  • 10-09-2022
  • Physics
contestada

'A drag racer starts from rest and accelerates uniformly to a speed of 76.5 m/s in 8.5 seconds. what is the distance traveled by the car in the 8.5 s?

Respuesta :

tanweeleong195oxyqwp
tanweeleong195oxyqwp tanweeleong195oxyqwp
  • 10-09-2022

Answer:

325.125m

Explanation:

We can use the kinematics equations to solve this problem.

Given:

u = Initial Velocity = 0 m/s

v = Final Velocity = 76.5 m/s

t = 8.5 s

We can use the first kinematics equation to find the acceleration:

v = u + at

76.5 = 0 + 8.5a

a = 76.5 ÷ 8.5

[tex] = 9\frac{m}{ {s}^{2} } [/tex]

Since we now have the acceleration, we can use the third kinematics equation to find the distance travelled:

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = (0)(8.5) + \frac{1}{2} (9) {(8.5)}^{2} \\ = 325.125m[/tex]

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