07-03-2017
Mathematics

contestada

How would you solve k^2-5k+6=0

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Аноним Аноним

07-03-2017

k2 + -5k + 6 = 0

6 + -5k + k2 = 0

6 + -5k + k2 = 0

Solving for variable 'k'.

Factor a trinomial. (2 + -1k)(3 + -1k) = 0 2 + -1k = 0 k = {2, 3}

hoped this helped i skipped some steps so you don't have to wait

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amazingmaddi amazingmaddi

07-03-2017

k^2-5k+6=0
k^2-5k=-6
k-2.23k=2.44
1.23k=2.44
k=1.99

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