Answer:
Step-by-step explanation:
Given: Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 5m and diagonal QS = 6m.
Since, diagonals of kite bisect each other, thus QP=6m
Now, in ΔPQR, we have
[tex](QR)^{2}=(RP)^{2}+(QP)^{2}[/tex]
[tex](5)^{2}=(3)^2+(RP)^2[/tex]
[tex]25=9+(RP)^2[/tex]
[tex]25-9=(RP)^2[/tex][tex]16=(RP)^2[/tex]
[tex]RP=4m[/tex]
Therefore, the length of segment RP is 4m.