given that cos Ф = 5/6 I know that one side is 5 and the hypotenuse is 6 so the other side is: a^2 = c^2 - b^2 a^2 = 6^2 - 5^2 a^2 = 36 - 25 = 11 a = [tex] \sqrt{11} [/tex]
Now I know that the sin is [tex] \frac{ \sqrt{11} }{6} [/tex] since sin is defined as opposite/hypotenuse
the second one uses a form of C = pi * d we are going to add the sector part to it. C = 6 and the central angle is 4 degrees we can set up like this: [tex]6 = \frac{4}{360}* \pi *d [/tex] [tex] \frac{6 * 360}{4 * \pi } = d
[/tex] d = 171.974 r = 171.94/2 =85.987
