RudyRomo RudyRomo

10-04-2017
Mathematics

contestada

((cot^2theta)/(1+csctheta))=((1-sintheta)/(sintheta))

Respuesta :

TheHero TheHero

10-04-2017

R.H.S = 1/sintheta - sintheta/sintheta = csctheta - 1

cot^2theta = csctheta^2 - 1 = (csctheta - 1) (csctheta+1)

L.H.S = (csctheta - 1)(csctheta+1)/1+csctheta = cscstheta - 1 = R.H.S

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