[tex]\bf \cfrac{x^3-1}{-3x+3}\\\\
-----------------------------\\\\
1=1^2=1^3=1^{100}=1^{1,000,000}\\\\
\textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-----------------------------\\\\
[/tex]
[tex]\bf \cfrac{x^3-1^3}{-3x+3}\implies \cfrac{(x-1)(x^2+x+1^2)}{-3(x-1)}\implies \cfrac{x^2+x+1}{-3}[/tex]
