cshepherd
cshepherd
08-05-2017
Mathematics
contestada
For y=e^(xlnx) find y'(e).
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EEPJR
EEPJR
08-05-2017
y = (e^(lnx))^x
y = x^x
y' = (x)x^(x-1)
y' = (x)(x^x)/x
y' = x^x
y'(e) = e^e
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