shellyannrussel shellyannrussel
  • 09-05-2017
  • Mathematics
contestada

8(x − 3) ≤ −4(x + 1)

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AlleyRedd
AlleyRedd AlleyRedd
  • 09-05-2017
x[tex] \leq [/tex] 5/3
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Crazyformath
Crazyformath Crazyformath
  • 09-05-2017
8(x-3)≤-4(x+1)
8x-24≤-4x-4
8x-(-4x)-24≤-4
8x+4x-24≤-4
12x-24≤-4
12x≤-4+24
12x≤20
x≤20/12
x≤5/3
Answer: x≤5/3


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