Seudónimo Seudónimo

09-04-2015
Mathematics

contestada

Solve.

8x + 4 ≤ –20

A.
x ≤ –3

B.
x ≤ –2

C.
x ≥ –2

D.
x ≥ –3

Respuesta :

mathgirl22 mathgirl22

09-04-2015

[tex]8x+4 \leq -20 \\ 8x+4-4 \leq (-20)-4 \\ 8x \leq -24 \\ \frac{8x}{8} \leq \frac{-24}{8} \\ \\ x \leq -3 \\ A[/tex]

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