Respuesta :

calculista

Answer:

[tex]6u^{2}+4u+6=0[/tex]

Step-by-step explanation:

we have

[tex]6(x-5)^{4}+4(x-5)^{2}+6=0[/tex]

Let

[tex]u=(x-5)^{2}[/tex]

remember that

if   [tex]u=(x-5)^{2}[/tex]

then

[tex]u^{2}=(x-5)^{4}[/tex]

substitute

[tex]6u^{2}+4u+6=0[/tex] -------> quadratic equation


amanisaleh20190

Answer:

the answer is (B) on ed2020

Step-by-step explanation:

B- 6u2 + 4u + 6 = 0, where u = (x – 5)2

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