[tex]\frac{k-3}{2}+3k+1+\frac{3k+1}{2}\\\frac{k-3}{2}+\frac{3k}{1}(\frac{2}{2})+\frac{1}{1}(\frac{2}{2})+\frac{3k+1}{2}\\\frac{k-3}{2}+\frac{3k*2}{2}+\frac{1*2}{2}+\frac{3k+1}{2}\\\frac{(k-3)+6k+2+(3k+1)}{2}\\\frac{10k+0}{2}\\\\5k[/tex]
Thus, the expression simplifies to become 5k.
