How do you write the equation? What is the solution on question 2

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Rileyjung73 Rileyjung73

06-05-2015
Mathematics

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How do you write the equation? What is the solution on question 2

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Panoyin Panoyin · Answer 1 · 2015-05-07T02:04:52+02:00

1x + 2y = 4 ⇒ 3x + 6y = 12
3x + 2y = 0 ⇒ 3x + 2y =   0
   4y = 12
      4 4
   y = 3
         x + 2y = 4
       x + 2(3) = 4
   x + 6 = 4
       - 6 - 6
   x = -2
   (x, y) = (-2, 2)

p = q + 2
3p + 2q = 9

    3(q + 2) + 2q = -9
3(q) + 3(2) + 2q = -9
      3q + 6 + 2q = -9
      3q + 2q + 6 = -9
      5q + 6 = -9
   - 6   - 6
      5q = -15
   5      5
   q = -3
p = q + 2
p = -3 + 2
p = -1
(p, q) = (-3, -1)