Answer with explanation:
The given expression is:
[tex]=\frac{2}{2+5 i}\\\\ \text{Rationalizing denominator}}\\\\=\frac{2\times (2-5i)}{(2+5i)(2-5 i)}\\\\=\frac{4-10 i}{2^2-(5i)^2}\\\\=\frac{4+5i}{4-25i^2}\\\\=\frac{4-10 i}{4+25}\\\\=\frac{4-10 i}{29}\\\\i^2=-1\\\\a^2-b^2=(a-b)(a+b)[/tex]
Option D
