hunterthompson2112 hunterthompson2112
  • 07-08-2017
  • Chemistry
contestada

The reactant concentration in a second-order reaction was 0.560 m after 115 s and 3.30×10−2 m after 735 s . what is the rate constant for this reaction?

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akiyama316
akiyama316 akiyama316
  • 17-08-2017
Use the formula for second order reaction:

[tex]\frac{1}{C} = \frac{1}{C_0} + kt[/tex]

C = concentration at time t 
C0 =  initial conc.
k = rate constant
t = time

1st equation :   [tex]\frac{1}{0.56} = \frac{1}{C_0} + 115k[/tex]

2nd Equation: [tex]\frac{1}{0.033} = \frac{1}{C_0} + 735k[/tex]

Find [tex] \frac{1}{C_0} [/tex] from 1st equation and put it in 2nd equation:

[tex]\frac{1}{0.033} = \frac{1}{0.56} - 115k + 735k[/tex]

[tex]\frac{1}{0.033} - \frac{1}{0.56} = 620k [/tex]

k = 0.046
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