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  • 07-02-2024
  • Chemistry
contestada

Starting with the following equation,

MgCl₂(aq) + Na₃PO₄(aq) → Mg₃(PO₄)₂(s) + NaCl(aq)

calculate the moles of MgCl₂ that will be required to produce 285 grams of Mg₃(PO₄)₂.

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