Respuesta :

Benjamin16
[tex]5x^{2}=-30x-65 \\ \\ 5x^{2}+30x+65 \ \ \ /:5 \\ \\ x^{2}+6x+13=0 \\ \\ \Delta=6^{2}-4*1*13=36-52=-16 \implies x\not\in R \\ \\ \sqrt{\Delta} =4i \\ \\ x_{1}= \frac{-6-4i }{2}= -3-2i \\ \\ x_{2}= \frac{-6+4i}{2}=-3+2i [/tex]
5x2=−30x−65

 Subtract -30x-65 from both sides.

5x2−(−30x−65)=−30x−65−(−30x−65)

5x2+30x+65=0

 Use quadratic formula with a=5, b=30, c=65.

x = −30±√−400 / 10

No solution.

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