drummerboy96 drummerboy96
  • 09-07-2015
  • Mathematics
contestada

Simplify the square root of 50x^7y^10

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Benjamin16
Benjamin16 Benjamin16
  • 10-07-2015
[tex] \sqrt{50x^{7}y^{10}} = \sqrt{50}* \sqrt{(x^{3})^{2}*x} * \sqrt{(y^{5})^{2}} =5 \sqrt{2}*x^{3} \sqrt{x} *y^{5}= \\ \\ 5x^{3}y^{5} \sqrt{2x} [/tex]
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