sydneyrae97 sydneyrae97
  • 09-09-2015
  • Mathematics
contestada

how do i solve

8x^(2/3)-39x^(1/3)-5=0

Respuesta :

ayah1
ayah1 ayah1
  • 09-09-2015
[tex]8 x^{ \frac{2}{3} } -39 x^{ \frac{1}{3} } -5=0[/tex]

[tex]8 \sqrt[3]{ x^{2} } -39 \sqrt[3]{ x^{1} } - 5=0[/tex]

[tex]8 \sqrt[3]{ x^{2} } -39 \sqrt[3]{ x } = 5[/tex]

[tex]8( \sqrt[3]{ x^{2} } )^{3} -39( \sqrt[3]{ x })^{3} =5 ^{3} [/tex]

[tex]8 x^{2} -39x =5 ^{3} [/tex]

[tex]8 x^{2} -39x =125[/tex]

[tex]8 x^{2} -39x - 125 = 0[/tex]

Hope this helps '-'

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