Respuesta :

x² + x - 12 factors into (x + 4) and (x - 3)
So if you set each factor equal to zero you get the following solutions
(x + 4) = 0   ⇒ x = -4  which cannot be "a" since a > 0 and -4 is not > 0
(x - 3) = 0   ⇒ x = 3 this is the value of "a"

answer: a = 3

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