TrucerZ3878 TrucerZ3878
  • 08-12-2017
  • Chemistry
contestada

551 cal of heat is added to 5.00 g ice at –20.0 °c. what is the final temperature of the water?

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Yna9141
Yna9141 Yna9141
  • 19-12-2017
This item can be answered using the equation,
  
               h = mcp(dT) + mHv

where h is the heat, m is the mass of the substance, cp is the specific heat, and dT is the temperature difference, Hv is the latent heat of fusion. Substituting the known values from the given above,

            551 cal = (5 g)(1 cal/g°C)(T - -20) + (5 g)(80 cal/g)

The value of T from the equation is 10.2.

Answer: 10.2°C
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