peterblessd6588 peterblessd6588
  • 09-01-2018
  • Mathematics
contestada

Find algebraically the zeros for p(x)=x^3+x^2-4x-4

Respuesta :

Аноним Аноним
  • 09-01-2018
One  zero is - 1
because p(-1) =  (-1)^3 + (-1)^2 -4(-1)- 4 = 0
So one factor of p(x) is x + 1
Dividing  p(x) by  x + 1  gives the quotient
x^2 - 4
x - 2)(x + 2) = 0

x = 2, -2


The zeroes are -2,-1 and 2
Answer Link

Otras preguntas

Stress surrounds us on a daily basis. Which of the following statements BEST describes ways to reduce or handle stress? A. Handling stress effectively involves
list 5 types of action energy and 4 types of potential energy
2. Order 3.3,3.19,3 1/5,3 1/3. 3. 20% of $1500 4. What fraction of 3 kg is 600 g? 5. 10 time its self by 3 times+10 times its self twice+10+1 6. How much is 6.7
How do you solve for B in 65pi=B5?
Jocy is making a wooden picture frame that will have a width that is 12 inches shorter than its length. If he uses 100 inches of wood, what are the dimsensionso
Why can't the intercepts, on their own, be used to graph the relation 5x + 9y = 0?
in the xy plane, what is the y intercept of the graph of the equation y=2 (x+3)(x+4)?
5000 is 1/10 of what
S=2(lw lh wh) solve for w
Why can't the intercepts, on their own, be used to graph the relation 5x + 9y = 0?