shannonsmyth91 shannonsmyth91
  • 06-03-2018
  • Mathematics
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2a(5-b)=3b+7 solve for b
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Аноним Аноним
  • 06-03-2018
2a(5-b)=3b+7

[open bracket]
10a - 2ab = 3b + 7

[solve for b, so we need to move all terms with b to the left]
[-3b on both sides]
10a - 2ab - 3b = 3b + 7 - 3b
10a - 2ab - 3b = 7

[move all those without b to the right]
[-10a on both side]
10a - 2ab- 3b - 10a = 7 - 10a
-2ab - 3b = 7 - 10a

[divide by -1 through to change b to be positive]
2ab + 3b = 10a - 7

[take b out as the common factor]
b(2a + 3) = 10a - 7

[divide by (2a+3) through]
b = (10a -7)/(2a+3)


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