1. Suppose that the amount of algae in a pond triples every 2 hours. If the pond initially contains 80 pounds of algae, how much algae will be in the pond after 8 hours? (1 point)
a) 720
b) 1,280
c) 6,480
d) 320
2 hours later = 3(80) 4 hours later = 3(3(80))) 6 hours later = 3(3(3(80))) 8 hours later = 3(3(3(3(3(80))))) 8 hours later = [tex] 3^{4} [/tex] x 80 8 hours later = 6480 (Answer C)
OR
We find the number of 2 hours period in that 8 hours 8 ÷ 2 = 4 It starts at 80 pounds It tripes every 2 hours Total algae = [tex] 3^{4} [/tex] x 80 = 6480 (Answer C)