zoefotinos
zoefotinos
08-03-2018
Mathematics
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caylus
caylus
08-03-2018
Hello,
[tex] \dfrac{10x-2}{8x} = \dfrac{5x+3}{7x} \\\\ x \neq 0\\\\ \dfrac{10x-2}{8} = \dfrac{5x+3}{7} \\\\ 70x-14=40x+24\\\\ 30x=38\\\\ x= \dfrac{19}{15} [/tex]
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