the molar mass of the components making up Ca(NO₃)₂ are as follows; Ca - 40 g/mol N - 14 g/mol O - 16 g/mol the molar mass of the compound is calculated as follows; Ca(NO₃)₂ --> 40 + 2(14 + 16x3) = 164 g/mol 1 mol of the compound weighs 164 g Therefore 0.433 mol = 164 g/mol x 0.433 mol = 71.0g the mass of 0.433 mol of the compound is 71.0 g
