Write log4 14 as a logarithm of base 3.

1) (log4)3/(log14)3
2) (log14)3/(log4)3
3) (log3)4/(log3)14
4) (log3)14/(log3)4,

Question

09-03-2018
Mathematics

contestada

Write log4 14 as a logarithm of base 3.

1) (log4)3/(log14)3
2) (log14)3/(log4)3
3) (log3)4/(log3)14
4) (log3)14/(log3)4,

Respuesta :

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Mindaka Mindaka · Answer 1 · 2018-03-22T17:03:41+01:00

Mindaka Mindaka

22-03-2018

The change-of-base formula for logarithms is:
loga (b) = [logc (b)] / [logc (a)]

where:
a = original base
b = original argument
c = new base

Hence,
log4 (14) = log3 (14) / log3 (4)

Therefore the correct answer is D.

Answer Link

Write log4 14 as a logarithm of base 3. 1) (log4)3/(log14)3 2) (log14)3/(log4)3 3) (log3)4/(log3)14 4) (log3)14/(log3)4,

Respuesta :

Otras preguntas

Write log4 14 as a logarithm of base 3.

1) (log4)3/(log14)3
2) (log14)3/(log4)3
3) (log3)4/(log3)14
4) (log3)14/(log3)4,