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The difference of sample means of two populations is 108.7, and the standard deviation of the difference in sample means is 32. Which statement is true if we are testing the null hypothesis at the 68% confidence level?

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Answer:

Step-by-step explanation:

Given that the difference of sample means of two populations is 108.7, and the standard deviation of the difference in sample means is 32.

H0: difference inmeans =0

Ha: difference inmeans not equal to 0

(Two tailed test)

Test statistic = mean difference/std deviation

[tex]=\frac{108.7}{32}\\=3.40[/tex]

For 68% confidence level, }z}<1

Here z =3.40 >1

Hence reject null hypothesis

The difference between the means cannot be 0 and there is statistical evidence at 68% level to reject null hypothesis

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