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10-04-2018
Mathematics

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how do you simplify square root of 5yv^2 sqaure root of 15y^2v^9

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Аноним Аноним

10-04-2018

[tex] \sqrt{5yv^{2} } = v \sqrt{5y} [/tex]
[tex] \sqrt{ {15y}^{2}2 {v}^{9} } \\ = yv^{4} \sqrt{15 \times 2v} \\ = y {v}^{4} \sqrt{30v} [/tex]
Hope this helps. - M

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