Answer:
[tex]6 {b}^{3} (2 {b}^{2} + 3b - 5)[/tex]
Step-by-step explanation:
The given expresion is
[tex] {12b}^{5} + 18 {b}^{4} - 30 {b}^{3} [/tex]
The greatest common factor is the greatest factor that is common to all the 3 terms.
We can see b³ is common to all the three terms.
Also 6 is common to all the three terms.
Hence the greatest common factor is 6b³
We factor the GCF to obtain:
[tex]6 {b}^{3} (2 {b}^{2} + 3b - 5)[/tex]
