skylerhabig skylerhabig
  • 06-08-2020
  • Mathematics
contestada

Which values of x are point(s) of discontinuity for this function? Function x = –4 x = –2 x = 0 x = 2 x = 4

Which values of x are points of discontinuity for this function Function x 4 x 2 x 0 x 2 x 4 class=

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 06-08-2020

Answer:

x=0 and x=2

Step-by-step explanation:

We need to check at each  point where the function changes definition

At x= -2

On the left side  -4   on the right side = -( -2)^2 = -4  continuous

At  x=0

The point is not defined since neither side has an equals sign

discontinuous

x =2

on the left side 2^2 =4  on the right side 2

It is discontinuous

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theLocoCoCo
theLocoCoCo theLocoCoCo
  • 28-09-2020

Answer:

x = 0

x = 2

Step-by-step explanation:

Edge 2020

~theLocoCoco

Answer Link

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